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FINAL FOUR

EAST/WEST Semi-Final:
A: Using A=1, B=2, etc, find the total letter value of the 5-letter name of the river that flows through two adjacent counties, whose names are the first and last names of the film character played by the actor who, in a different film from the same decade, played a character whose first name is  [also that of a county in GA, next to a 4-letter county beginning with the same letter, and also a county in SD next to a 7-letter county beginning with the first letter of the last name of the author of this puzzle]*, and whose surname is [ ]* (same as brackets above, except substitute TX for GA and IL for SD)
Z: $A bonus, offered to B by the owner of the C's to develop his signature D...divided by E digits -
and not the ones represented by F's [who had no D, and who won G championships as a coach, the second-most number of championships in the history of his pro sport for a coach] on his H's (a la the evil clan among testudines); but by B's (including the sign of approval of a TV character, whose signature line is an elongated C) on his I's (the CEO of a NYSE-traded company which has an anagram that might describe how his employees see him, and another anagram that might describe the company's end product use) - associated with J, who has a D and does the same thing as B, whose number, K, is associated with a movie whose star had a D in the movie, and whose signature line gives the house a 5.26% advantage and whose 2005 team, L, is also the name of a coast guard vessel represented by what might be quitting time for a dyslexic...plus G multiplied by M, the number of pro championships earned as a coach by N (who had no D), who was a rival of F in the same sport, where a N is delivered by reorienting and projecting the B...plus O, the atomic number of the NYSE trading symbol of I's company.
In other words, (A/E) + (GxM) + O
[Note that B's D is the same variety as that of a president born in a year ending in K, and no president since has had a D of any description.]

NORTH/SOUTH Semi-Final:
A: Sum of the nine digits of an integer which can be expressed as the product of three prime numbers of three digits or greater, two of which begin with a digit not represented in the nine-digit number and none of which contain the only digit that appears twice in the nine-digit number, and which can also be expressed, after a display of calculated manipulation, of the common bond between seven individuals whose two-word names have each been anagrammed into two other words, all rearranged and listed below.

YODELED

BEER

UNLAYS

TUSKS

CONVERT

BRINER

FANS

GRADIENT

SHIVER

CAPLET

CAMELOT

ANYONE

SOLDIERS

ADORN

Z: You and I are playing a game of Scrabble. You hold BIKOWY plus a blank and score a whopping 96 points on the first play of the game. I, holding BEEGGMN, am happy you played an I, and I get a bingo for 65. You stare at your second rack (DEIIOXZ). “How can anyone make a word out of these lousy letters?” you wonder, and exchange all of them. My second rack is EEFJLRU. I manage to clean up my rack nicely, using six of my letters, but score a mere 17 points and open up a risky hot spot. Meanwhile, your next rack (CLMNRTU) seems to be even worse than the one you just threw in, but you don’t want to trade twice in a row lest you fall too far behind. How many points can you score for your best play?

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Comments

Hi,

Yikes!...Brain overload!

Is it possible you could extend the deadline?

Posted by: Jim from Minnesota | Apr 1, 2006 4:21:39 PM

Looking at the 9-digit product of 3 primes, nice job putting it together! Still trying to figure out how to pair up those 14 words to get 7 names. I guess each pair will be a little easier than the last. A couple of questions I hope weren't intended to be vague: Where it says, "...two of which begin with a digit not represented...", does that mean two of the primes begin with the same digit, or might these be two different digits, each not found in the product? Also, does "...digit that appears twice..." mean EXACTLY twice, or AT LEAST twice?

Posted by: Bob Lodge | Apr 1, 2006 5:00:31 PM

Scrabble question...very nice.

Posted by: Michael | Apr 2, 2006 12:53:43 PM

From the creator:

Yes, two of the primes do begin with the same digit that is not found in the product. The digit in question that appears twice does appear exactly twice in the 9-digit prime number.

Posted by: JmSR | Apr 3, 2006 7:43:34 AM

That Scrabble clue may be favorite clue ever in any puzzle on this site.

Posted by: DJ | Apr 3, 2006 7:43:54 PM

With a puzzle like this, the grand prize should be a nice vacation in the place where the NCAA champs come from.

Posted by: Ross | Apr 4, 2006 6:25:17 AM

I'll remember that when the champion is someone like UConn.

Posted by: JmSR | Apr 4, 2006 7:02:31 AM

No - I think putting the names togetherr gets harder after the first few!

Posted by: Paula | Apr 4, 2006 1:11:50 PM

EAST/WEST
A: Declarative State 37
Z: University of Catan 64 W

A: Hopefully the style and structure of the puzzle was recognizable as being authored by Bob Lodge. The only 7-letter county beginning with L in SD is Lincoln, adjacent to 4 other counties, which can be checked against county names in GA for one which is additionally adjacent to a 4-letter county beginning with the same letter. Turner and Tift do the trick.

Similarly, in IL only LaSalle Co has initial L and 7 letters, and of the 9 adjacent county names, TX yields Kendall, next to Kerr.

The character Turner Kendall appears in The Morning After (1986) and was played by Jeff Bridges. Checking other characters he played in the 1980s whose first and last names show promise as county names, success is met with his 1988 portrayal of Preston Tucker, also the names of two adjacent counties in WV.

They are traversed by the CHEAT river, whose letter values add to 3+8+5+1+20 = 37. Bob Lodge, writer.

Z: Answer: 64

Explanation:
$300 bonus, offered to Rollie Fingers by the owner of the Oakland As to develop his signature handlebar moustache...divided by 12 digits (fingers, not toes) - and not the ones represented by Toes (Toe Blake) [who had no moustache, and who won 8 championships as a coach for the Montreal Canadiens, the second-most number of championships for a coach in the history of the NHL] on his Feet (Foots) (a la the evil Foot clan
from the Teenage Mutant Ninja Turtles (turtles are testudines)); but by Fingers (including thumbs - the sign of approval (thumb) of the Fonz, whose signature line is Ayyyy (Oakland As)) on his Hands (Scott Hand,
the CEO of Inco (N), which has an anagram that might describe how his employees might see him (icon), and another anagram that might describe the company's end product use (coin)) - associated with pitcher Antonio
Alfonseca, who has a moustache, whose number 57 is associated with a movie Passenger 57 whose star Wesley Snipes had a moustache in the movie, and whose signature line (Always Bet on Black) gives the house
a 5.26% advantage (in American Roulette) and whose team, The Florida Marlins, is also the name of a coast guard vessel (Martin P5M Marlin) represented by what might be quitting time for a dyslexic (5PM)...plus
8 multiplied by 4, the number of pro championships earned as a coach by Punch Imlach (who had no moustache), who coached the Toronto Maple Leafs and was a rival of Toe Blake in the NHL, where a punch is delivered by reorienting and projecting the fingers...plus 7, the atomic number of
Nitrogen (N), where N is the symbol of INCO on the NYSE.

In other words, (300/12) + (8 x 4) + 7 = 64.

[Note that Rollie Fingers' moustache is the same variety (handlebar) as that of President Taft (born in 1857), and no president since has had a moustache of any description.]

A = 300
B = Rollie Fingers
C = A's
D = Moustache
E = 12
F = Toe Blake
G = 8
H = Foot Clan
I = Scott Hand (Inco)
J = Antonio Alfonseca
K = 57
L = Marlins
M = 4
N = Punch Imlach
O = 7 (Nitrogen)
Michael Pickard, writer.

NORTH/SOUTH
A: Duchess 44
Z: Electoral College 73 W

A:The anagrammed names are as follows:
ADORN + SHIVER = DEVON HARRIS
CALUMNY + SOLATE = SAMUEL CLAYTON
ANYONE + CONVERT = YVONNE CERNOTA
HEMATIC + WHILE = MICHAEL WHITE
REPLICA + BRENT = PRINCE ALBERT
GRADIENT + FANS = STEFAN GRANDI
TUSKS + YODELED = DUDLEY STOKES

If you look down the 3rd column of the word list upside-down you can see OLYMPIAN IN SLED. Also, a few of the words (SHIVER, GRADIENT, FANS) could (okay, might) bring about imagery of bobsledding, just to confirm that you were on the right track.

Each of the individuals listed are athletes who have competed in Olympic bobsleigh. In addition, each of these athletes has made headlines due to an accident involving an overturned bobsleigh.

If you look at the letters in bobsleigh, you can represent these letters on an upside-down LCD calculator (i.e. the overturned bobsleigh and a display of calculated manipulation)

bObSLEIgh = 461375909

257*277*6481 = 461375909

4+6+1+3+7+5+9+0+9 = 44. Jay Winter, writer.

Z: Solution: Hopefully you will notice that this cannot be done with real Scrabble words. The words played are all ones coined on The Simpsons. The first move is KWYJIBO, with the blank a J. The second is EMBIGGEN
through the I. After you exchange OXIDIZE, I play FLUNJER through the N. Your best play is CROMULENT, through the O of KWYJIBO and the E of FLUNJER, for
73 points.

Answer: 73. Will Nediger, writer.

Posted by: JmSR | May 1, 2006 9:07:03 AM

JM,

I had updated the bobsleigh question to change Michael White (too easy to un-anagram HEMATIC to Michael) to Ilse Broeders (BEER + SOLDIERS). I think I sent you an updated answer key to match, where a few of the name anagrams were changed to make the "OLYMPIAN IN SLED" still work out...but this post probably provides all the update needed.

Posted by: Jay Winter | May 1, 2006 9:18:00 AM

The best clue in the Simpsons Scrabble question was the OXIDIZE combined with the "How can anyone make a word out of these lousy letters?” A direct Google on this phrase, after the UCDP comes up first, will yield a number of references to the Simpsons episode "Bart the Genius", which should get you to kwyjibo, and down the right path.

Posted by: Jay Winter | May 1, 2006 9:20:23 AM

Hi,

I have an alternate answer for Michael Pickard's question...

I found a Marlin's pitcher named CHAD BENTZ who used to wear the number 57 for another team & occasionally wore a mustache...

He only has 6 fingers in all...

So I had (A/E [300/6 = 50]) + (GxM [8X4= 32]) + O[7] [89 IS FINAL ANSWER]....

Could this be an alternate answer?...

Posted by: Jim from Minnesota | May 1, 2006 9:59:13 PM

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